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[News] Late For Work 6/15: What Could Ravens Get In Trade For Eugene Monroe?

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Assuming both the man and the house are in the middle, and unidimensional, 0.2 ft for a 6-foot man and 5 ft for a 30-ft house.

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I'm with Zrebiec on this one. When the trade is about the original team wanting to get rid of the player (like in the case of Boldin or Ngata) rather than the new team wanting to get the player (like with Zuttah), the compensation is always less than the player would be worth. Anyone who thinks a 6th rounder is a shame, just think about it: we got 6th rounders for Boldin and Ngata too... Because it's the pick PLUS the freed up cap space that's the real gain here, not only the pick.

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@bostonraven - not quite

Assuming the man stands in the middle, we're lifting up the rope in the middle to create two right triangles.  We know that height of each triangle is 6' and length is 60', so we can use the Pythagorean Theorem to figure out the length of the hypotenuse.  60^2 + 6^2 = 3600 + 36 = 3636 = c^2, so c = 60.299 feet.  So the length of the rope with a man standing in the middle is 2*c = 120.5980, which means we need to add 0.5980 feet, or 7.18", to the rope in order to fit the man under it.

Not going to do the math for the house, but it's the same calculation using a height of 30'

Just give me a beer and tell me when you have the answer.

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I'm with Zrebiec on this one. When the trade is about the original team wanting to get rid of the player (like in the case of Boldin or Ngata) rather than the new team wanting to get the player (like with Zuttah), the compensation is always less than the player would be worth. Anyone who thinks a 6th rounder is a shame, just think about it: we got 6th rounders for Boldin and Ngata too... Because it's the pick PLUS the freed up cap space that's the real gain here, not only the pick.

I'd be OK with a 5th or 6th but with time winding down I think teams are thinking they will just wait until he is released.

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I'm with Zrebiec on this one. When the trade is about the original team wanting to get rid of the player (like in the case of Boldin or Ngata) rather than the new team wanting to get the player (like with Zuttah), the compensation is always less than the player would be worth. Anyone who thinks a 6th rounder is a shame, just think about it: we got 6th rounders for Boldin and Ngata too... Because it's the pick PLUS the freed up cap space that's the real gain here, not only the pick.

Is so hard to tell. It all depends on how who needs a tackle, and how badly they need one. If a team feels its a tackle away from being a legitimate playoff contender they might be willing to give up more. And Boldin and Ngata were traded to free up cap space, while Monroe is simply being traded because they don't feel like paying him.

Personally, I think its a weird time to trade him. They are evidently very confident in Stanley, but why not keep him into the preseason and shop him like they did with Mark Clayton. That way teams will know if they oline help, and they could actually be a bidding war, but I don't see them getting anything higher then a 5th round pick.

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@bostonraven - not quite

Assuming the man stands in the middle, we're lifting up the rope in the middle to create two right triangles.  We know that height of each triangle is 6' and length is 60', so we can use the Pythagorean Theorem to figure out the length of the hypotenuse.  60^2 + 6^2 = 3600 + 36 = 3636 = c^2, so c = 60.299 feet.  So the length of the rope with a man standing in the middle is 2*c = 120.5980, which means we need to add 0.5980 feet, or 7.18", to the rope in order to fit the man under it.

Not going to do the math for the house, but it's the same calculation using a height of 30'

I agree with you, except that you are mixing feet and yards. The man is 6 feet while the rope is 120 yds. so it is 6^2 + 180^2 = c^2. So 32436 = c^2. c=180.099. So each side of the rope needs that length added, so 2c=360.199ft. .2 ft needs to be added or 2.4 inches.

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The maths problem only requires the use of the Pythagorean theorem (a2+b2=c2) where a is the half of the rope's length (60 yards or 360 feet), b is the height of the man/building that must fit under the slackened rope (6 or 30 feet) and c is half of the slacked rope's length. So, it goes (figures are in feet)

1802+62=c2

32,400+36=c2

32,436=c2

180.1=c

This is half of the slackened rope's length, which puts the total (slacked) rope length at 2*180.01=360.02; the original rope length is 360 feet (120 yards), so the required slack for a 6-foot man to fit under the rop is 0.02 feet, or abour 0.24 inches.

 

For the 30-feet buliding, the same method gives a slack of 4.96 feet.

 

Edited by bioLarzen
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48 minutes ago, NoCookies28 said:

@bostonraven - not quite

Assuming the man stands in the middle, we're lifting up the rope in the middle to create two right triangles.  We know that height of each triangle is 6' and length is 60', so we can use the Pythagorean Theorem to figure out the length of the hypotenuse.  60^2 + 6^2 = 3600 + 36 = 3636 = c^2, so c = 60.299 feet.  So the length of the rope with a man standing in the middle is 2*c = 120.5980, which means we need to add 0.5980 feet, or 7.18", to the rope in order to fit the man under it.

Not going to do the math for the house, but it's the same calculation using a height of 30'

I think you've made a little mistake here by putting the guy's height at 6 yards instead of 6 feet.

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3 minutes ago, bioLarzen said:

The maths problem only requires the use of the Pythagorean theorem (a2+b2=c2) where a is the half of the rope's length (60 yards or 360 feet), b is the height of the man/building that must fit under the slackened rope (6 or 30 feet) and c is half of the slacked rope's length. So, it goes (figures are in feet)

1802+62=c2

32,400+36=c2

32,436=c2

180.1=c

This is half of the slackened rope's length, which puts the total (slacked) rope length at 2*180.01=360.02; the original rope length is 360 feet (120 yards), so the required slack for a 6-foot man to fit under the rop is 0.02 feet, or abour 0.24 inches.

 

For the 30-feet buliding, using the same principle, gives a slack of 4.96 feet.

 

Just as long as the man isn't in pads for 5 minutes during voluntary OTAs.

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The maths problem only requires the use of the Pythagorean theorem (a2+b2=c2) where a is the half of the rope's length (60 yards or 360 feet), b is the height of the man/building that must fit under the slackened rope (6 or 30 feet) and c is half of the slacked rope's length. So, it goes (figures are in feet)

1802+62=c2

32,400+36=c2

32,436=c2

180.1=c

This is half of the slackened rope's length, which puts the total (slacked) rope length at 2*180.01=360.02; the original rope length is 360 feet (120 yards), so the required slack for a 6-foot man to fit under the rop is 0.02 feet, or abour 0.24 inches.

 

For the 30-feet buliding, using the same principle, gives a slack of 4.96 feet.

 

bioLarzen, your observations and critiques on this site are usually spot-on, and I am a fan. But in this particular case, I gotta say that the decimal places are really important *smiley face*

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Nobody is going to give up a thing for Monroe at this point, when they can just wait for the Ravens to cut him. Maybe Ozzie is trying to light a fire under him to perform this year. When he plays, he's pretty good.

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  14 minutes ago, bioLarzen said:

The maths problem only requires the use of the Pythagorean theorem (a2+b2=c2) where a is the half of the rope's length (60 yards or 360 feet), b is the height of the man/building that must fit under the slackened rope (6 or 30 feet) and c is half of the slacked rope's length. So, it goes (figures are in feet)

1802+62=c2

32,400+36=c2

32,436=c2

180.1=c

This is half of the slackened rope's length, which puts the total (slacked) rope length at 2*180.01=360.02; the original rope length is 360 feet (120 yards), so the required slack for a 6-foot man to fit under the rop is 0.02 feet, or abour 0.24 inches.

 

For the 30-feet buliding, using the same principle, gives a slack of 4.96 feet.

 

bioLarzen, your observations and critiques on this site are usually spot-on, and I am a fan. But in this particular case, I gotta say that the decimal places are really important *smiley face*

Agree with all points

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I say keep Monroe until final cuts and just let him sit there. Don't let him get in football shape, don't let him do any work for risk of injury and just wait and wait for a team here or there to lose a left tackle to injury. There is no market now but what is the hurry to get rid of him? Who can we put in that 90th roster spot other than Monroe that will make a difference? No one. Same with the 75 man roster. Keep Monroe until the final cuts and if no one offers anything, we have lost nothing by waiting, but, his value continues to increase as time goes by and more left tackles get beat up in training camp. If we end up cutting him at the end of august, he won't be able to get anything in the way of a contract. He will have been sitting all summer, will be out of football shape and he can dedicate his time to his true love, not football, but promoting pot. Good for him for taking a stand, but do it on your time, don't drag your team into it and don't cry if they don't run out and holler from the highest mountain that they support him. He has been a slacker since day one.

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If Fletcher Cox got $17 million a year why would Williams get 15?I'd be surprised if he got more than the $9.2 million Damon Harrison got this offseason.D lineman who average 1 or 2 sacks a year aren't worth anything in the teens in todays NFL.

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  1 hour ago, bostonraven said:
  1 hour ago, bioLarzen said:

The maths problem only requires the use of the Pythagorean theorem (a2+b2=c2) where a is the half of the rope's length (60 yards or 360 feet), b is the height of the man/building that must fit under the slackened rope (6 or 30 feet) and c is half of the slacked rope's length. So, it goes (figures are in feet)

1802+62=c2

32,400+36=c2

32,436=c2

180.1=c

This is half of the slackened rope's length, which puts the total (slacked) rope length at 2*180.01=360.02; the original rope length is 360 feet (120 yards), so the required slack for a 6-foot man to fit under the rop is 0.02 feet, or abour 0.24 inches.

 

For the 30-feet buliding, using the same principle, gives a slack of 4.96 feet.

 

bioLarzen, your observations and critiques on this site are usually spot-on, and I am a fan. But in this particular case, I gotta say that the decimal places are really important *smiley face*

Agree with all points

What about the width of the 6' tall man's head?

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i would hold onto monroe unless a team offers a 4th or better which will not happen. we need to keep him until we know stanley can handle the job in full pads and contact and that we have a better backup than hurst in place. hurst is better suited as a rt or guard imo.

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Why the rush to dump Monroe? Whatever happened to playing the best five on the OL?  Reminds me of our rush to dump "Q"... we all know what a disaster that decision was.  I wonder who is calling this shot?

Edited by b93333
Didn't finish thought
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The maths problem only requires the use of the Pythagorean theorem (a2+b2=c2) where a is the half of the rope's length (60 yards or 360 feet), b is the height of the man/building that must fit under the slackened rope (6 or 30 feet) and c is half of the slacked rope's length. So, it goes (figures are in feet)

1802+62=c2

32,400+36=c2

32,436=c2

180.1=c

This is half of the slackened rope's length, which puts the total (slacked) rope length at 2*180.01=360.02; the original rope length is 360 feet (120 yards), so the required slack for a 6-foot man to fit under the rop is 0.02 feet, or abour 0.24 inches.

 

For the 30-feet buliding, the same method gives a slack of 4.96 feet.

 

For the house, assuming it's not an A-frame or a tepee, I believe you're going to need the width of the house at the roof level to complete your calculations. Your calculations work for a pole, not a polygon which most houses appear to be when viewed from one of its sides.

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Why the rush to dump Monroe? Whatever happened to playing the best five on the OL?  Reminds me of our rush to dump "Q"... we all know what a disaster that decision was.  I wonder who is calling this shot?

You know as soon as Ravens trade him the Ravens will need to start looking for replacement because either the starter will get hurt or the trade e will get hurt. This is is getting like the SAINTS used to be. No luck anymore.

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Why the rush to dump Monroe? Whatever happened to playing the best five on the OL?  Reminds me of our rush to dump "Q"... we all know what a disaster that decision was.  I wonder who is calling this shot?

We save 4.5 million on cap space and 2 million to dead money. Your comparing apples to oranges not the same as Q. Monroe sucks even when healthy which has not been much lately.

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Nobody is going to give up a thing for Monroe at this point, when they can just wait for the Ravens to cut him. Maybe Ozzie is trying to light a fire under him to perform this year. When he plays, he's pretty good.

I don't know what you have been watching but I just don't agree with he is pretty good. Hello, Jacksonville drafted him pretty high then got rid of him to us for a 4th & 5th round pick a few years later. Ozzie made a terrible move giving him the big bucks. He has sucked ever since plus now he is a Pot head.

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Math problem is EZ. Simple pythagorean theorem. a^2+b^2=c^2, where the answer is 2x the difference between C and B (assuming B is the 60 yards).

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52 minutes ago, PalmBayRaven said:

We save 4.5 million on cap space and 2 million to dead money. Your comparing apples to oranges not the same as Q. Monroe sucks even when healthy which has not been much lately.

Actually it's 2.5 million in cap space or somewhere in those lines and 4.5 million in dead cap. 

I'd be inclined to say we keep him unless we are blown out of the water with a good deal such as the 4th that was mentioned above or a decent ILB / player that is needed in a position of need.  Having two LT isn't  such a bad idea.  When Monroe is on the field he is pretty good. 

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  1 hour ago, b93333 said:

Why the rush to dump Monroe? Whatever happened to playing the best five on the OL?  Reminds me of our rush to dump "Q"... we all know what a disaster that decision was.  I wonder who is calling this shot?

We save 4.5 million on cap space and 2 million to dead money. Your comparing apples to oranges not the same as Q. Monroe sucks even when healthy which has not been much lately.

But what about Stanley. Are you sure he's really ready to handle the starting LT spot on the first game of the season? I would wait until preseason to decide if to release or trade Monroe because if Stanley is struggling the first game, Joe will be on his back and then we are in trouble than the early trade of Monroe would be stupid. Monroe is the best quality LT we have. I would wait first if l was Ozzie because l don't want to take that risk at the beginning of the season.

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I think all the comments that talk about triangles are incorrect, if you assume it's a "real" object, because a rope with mass does not hang in a triangle shape. Hanging ropes with slack in them take the shape of a catenary, AKA a hyperbolic cosine. In this case it's half a catenary, since the tall part is in the middle. Given that the function has a value of 2 at position 60, and a value of zero at position zero, I calculate that the function for the rope's height is f(x) = cosh (x/34) - 1. Calculating arclength of this function from zero to 60, and multiplying by 2, I conclude the rope will have a total length of 120.1 yards.

Edited by merryjman
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If we could get a pick for Monroe and someone would take on his salary, that sounds good, but I don't see the point in cutting him right now. We don't need the cap space this year, so we might as well keep him for depth, kind of like how we kept Bryant Mckinnie for depth during the SB year. Also, if we wait until next year to cut him, it will save us a lot of cap space in 2017.

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